00:04
For this question, we're doing a neutralization between hydrochloric acid and magnesium hydroxide.
00:11
This would produce magnesium chloride and water to balance a two in front of the hcl and a two in front of the hc2o.
00:20
We'll start by calculating total moles of the hydrochloric acid, which would be equal to the molarity.
00:28
0 .953 molar times the volume converted to liters, which would be 25 milliliters or 0 .0250 liters.
00:47
And this would give us 0 .038 moles of hcl.
00:56
And then we can calculate the unreacted moles of hcl and this would be 0 .602 moles of any o h per liter times 12 .29 mil liters we'll convert that to liters so 0 .0 .0 .0 .029 liters and then we know in this neutralization, one mole of n -a -o -h reacts with one more.
01:49
This is going to give us 0 .00740 moles of hcl.
01:57
So from this we can calculate the moles of magnesium hydroxide, as that's equal to the difference here.
02:13
0238 moles of hcl minus .00740 moles of hcl.
02:20
And then from our balanced equation up above, we know that.
02:23
2 moles of hcl react with 1 mole magnesium hydroxide...