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Problem 51 Hard Difficulty

Magnesium metal (a component of alloys used in aircraft and a reducing agent used in the production of
uranium, titanium, and other active metals) is isolated from sea water by the following sequence of reactions:
$\mathrm{Mg}^{2+}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \longrightarrow \mathrm{Mg}(\mathrm{OH})_{2}(s)+\mathrm{Ca}^{2+}(a q)$
$\mathrm{Mg}(\mathrm{OH})_{2}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{MgCl}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)$
$\mathrm{MgCl}_{2}(l) \stackrel{\text { electrolysis }}{\longrightarrow} \mathrm{Mg}(s)+\mathrm{Cl}_{2}(g)$
Sea water has a density of 1.026 $\mathrm{g} / \mathrm{cm}^{3}$ and contains 1272 parts per million of magnesium as $\mathrm{Mg}^{2+}(a q)$ by mass. What mass, in kilograms, of $\mathrm{Ca}(\mathrm{OH})_{2}$ is required to precipitate 99.9$\%$ of the magnesium in $1.00 \times 10^{3} \mathrm{L}$ of sea water?

Answer

3.99 $\mathrm{Kg}$

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Chemistry 102

Chemistry

Chapter 15

Equilibria of Other Reaction Classes

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Chemical Equilibrium

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Video Transcript

here to calculate the amount of magnesium to positive present in sea water. We need to use care speed. First of all, we need to determine the mass off MG riches. One point Siegel. 10 days to go. Three leaders multiplied with 1000 sending me the cube. When do you do six grand per centimeter cube multiplying with 1272 parts per 1,000,000. This gives the marks as one point 30 for you 10 days toe three grounds. The concentration is this. If 99.9 is Toby the covered, that means Tzeitel 0.999 1.305 clams per litre will be called off 1.304 grams per leader as far as 99.9% 8 The mullahs Concentration can be calculated as do I did play 24.30 Flame grandpa More on for gram per liter. The mullahs Concentration Donato 0.0 53 65 As for calcium hydroxide reaction with magnesium on one racial one molar basis, the amount for calcium hydroxide quiet can be represented. US. 0.0 by 365 Monkey played with 74.0 mine Grandpa, move off. Calcium hydroxide will be equal to three point 97 Crumple leader for the for treatment for 1000 liters we have So the little 3.97 grams per liter equals two. 3.97 Multiply 10 days to put three crowns, which is equal to 3.97 kilograms. We need to wear which negative ions. So magnesium oxide McNish in my dark side. B m jean Positive Plus two Which negative which gives which is already provided The GSP value has 1.5 multiply 10 days to plan negative 11 When initial concentration off 1.3 In the initial concentration off 1.3 five Grand's for leader is reduced to 0.1% off the original. The polarity can be calculated as arms. Alito, divided by grams for more equals five point 369 10 days to one negative. Five more, adding the which negative I'm required the formula for Seoul ability substituting in the values we have, which negative ways to power, too, equals one point for you. Mainly stupid Negative 11. Already given. Divided by 5.369 10 days to one negative, are you? What time concentration. Turn out to be your 0.29 Multiply 10 days to open negative for Mondo, hence on additional half. Why you point 29 Multiply 10 based upon negative. Four more multiplied with 2.65 Tim Lister one negative four more Both calcium hydroxide for leader is required to supply the witch Negative. I'm 4000 later hence the mosque or see you, which can be calculated as to a 0.65 Want to pretend this two point negative for worn off catcher Mike Brooks? Eight. Our leader multiplied with 10 days to power. Three. Finally, it really does. Seven A four point Siegel 94 Divided by wool of calcium hydroxide. This gives us 20 crumbs, which is equal to 0.0 so zero kilograms hands. The total cash in hydroxide require can be calculated as 3.97 kilograms plus zero point Siegel Luisito, which gives us three point 99 killer runs

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Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson

Chemistry

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