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Make a drawing similar to Figure 23.14, but with the pendulum moving in the opposite direction. Then use Faraday’s law, Lenz’s law, and RHR-1 to show that magnetic force opposes motion.

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Physics 102 Electricity and Magnetism

Chapter 23

Electromagnetic Induction, AC Circuits, and Electrical Technologies

Electromagnetic Induction

Cornell University

University of Michigan - Ann Arbor

University of Washington

University of Sheffield

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

07:47

Use Faraday's law, Le…

04:56

You have the apparatus sho…

06:39

To measure a magnetic fiel…

00:15

A bar magnet is spun at co…

01:35

Part of a long wire carryi…

02:28

02:52

An electric motor has a sq…

02:29

Consider a solenoid of len…

02:54

Design a current loop that…

03:35

Predict/Calculate The magn…

00:57

Draw a small bar magnet an…

09:15

01:52

An electromagnet produces …

09:12

A magnetic field passes th…

03:26

Use Newtonian circular mot…

03:32

\bullet A long, straight w…

02:38

Find the direction of the …

06:31

ssm The rectangular loop i…

02:55

Find the magnetic flux thr…

01:11

A bar magnet is initially …

this to be the diagram with the pendulum moving in the opposite direction, where the velocities, of course, going Ah, clockwise in this sense and so we can say that then a CZ the plaint as a plate enters from the right because I as a plate enters from right, we get that the flux increases due to which and Eddy current is set from Faraday's law. We can say at this point this would be this Eddy Current would be in the counter clockwise direction so as to decrease resultant flux from lenses law. We can then say that the force on the left side of the loop, because they force on left side of current loop is and B right direction when the plate leaves the when the plate leaves the field. The Eddy current is now clockwise since the flux is decreasing. So we can say that then, um, when plate leaves field study current is clockwise because flux is decreasing and finally, we can then say that again there is a force, um, after again after the plate leaves the field, there is a forth on the current loop again to the right direction. That is the end of the solution. Thank you for watching

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