Question
Make a geometric construction (or use trigonometry) to show that Venus's orbit is about 0.72 times the size of Earth's, based on the fact that Venus's greatest elongation is $47^{\circ}$.
Step 1
The greatest elongation of a planet is the maximum angular distance from the Sun at which the planet can be observed from Earth. For Venus, this is given as \(47^{\circ}\). Show more…
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Given that the angular size of Venus is $55 "$ " when the planet is $45,000,000 \mathrm{km}$ from Earth, calculate Venus's diameter (in kilometers)
The elongation of the planet Venus is defined to be the angle $\theta$ determined by the sun, Earth, and Venus, as shown in the figure. Maximum elongation of Venus occurs when Earth is at its minimum distance $D_{e}$ from the sun and Venus is at its maximum distance $D$, from the sun. If $D_{e}=91,500,000 \mathrm{mi}$ and $D_{y}=68,000,000 \mathrm{mi}$ approximate the maximum elongation $\theta_{\max }$ of Venus. Assume that the orbit of Venus is circular. (IMAGE CAN NOT COPY)
The Trigonometric Functions
Applied Problems
Distance from Venus to the Sun The elongation $\alpha$ of a planet is the angle formed by the planet, earth, and sun (see the figure). When Venus achieves its maximum elongation of $46.3^{\circ},$ the earth, Venus, and the sun form a triangle with a right angle at Venus. Find the distance between Venus and the sun in astronomical units (AU). (By definition the distance between the earth and the sun is $1 \mathrm{AU}$.)
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