00:01
We are given the composition, mass composition of meta -acid.
00:04
So we have 41 .39 % carbon and 3 .472 to the semi -hydrogen and the rest of oxygen.
00:10
And also we're given if we have 2 .19 more of that meta -acet, we have 15 gram.
00:15
So what would be the empirical formula and also molecular formula? all right, so the first thing we can find will be the mass potential stage of oxygen.
00:24
Because we only have three elements, so we're going to subtract, take the 100%, to subtract the percentage of carbon and also that of hydrogen.
00:35
And then we should be able to find that the percentage of also just 35 .14.
00:42
Okay, so that's the first one we can do.
00:44
Second, we can actually find out the motor mass from our information over here.
00:50
Okay, so if we remember, number of molecules to mass divided by the molar mass.
00:57
So, number of moles is equal to mass, divided by molar mass, and we want to find the molar mass.
01:04
So we're going to take a number of mole divide by, sorry, the mass divided by the number of mole, and then we'll have the molar mass.
01:10
All right, so we are going to take 15, the mass divided by the lumber of mole, and then we should be able to find that the molar mass if we're around 1 .16 .3 gram per mole.
01:24
So this is the motor mass of metal acid.
01:28
Okay, so from here we can use our motor mass assume we have one mole to find the corresponding mass of carbon, hydrogen, and oxygen.
01:36
Okay, so we are going to assume have one mole of compound...