Many metals react with oxygen gas to form the metal oxide. For example, calcium reacts as follows:

$$

2 \mathrm{Ca}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CaO}(s)

$$

You wish to calculate the mass (g) of calcium oxide that can be prepared from 4.20 $\mathrm{g}$ of $\mathrm{Ca}$ and 2.80 $\mathrm{g}$ of $\mathrm{O}_{2} .$

(a) What amount (mol) of $\mathrm{CaO}$ can be produced from the given mass of Ca?

(b) What amount (mol) of CaO can be produced from the given mass of $\mathrm{O}_{2} ?$

(c) Which is the limiting reactant?

(d) How many grams of CaO can be produced?

a) $\mathrm{n}(\mathrm{CaO})=\mathrm{n}(\mathrm{Ca})=0,105 \mathrm{mol}$

b) $\mathrm{n}(\mathrm{CaO})=2 \mathrm{n}\left(\mathrm{O}_{2}\right)=0,175 \mathrm{mol}$

c) Ca

d) $\mathrm{m}(\mathrm{CaO})=5,88 \mathrm{g}$

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Carleton College

University of Central Florida

Numerade Educator

University of Toronto

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