00:01
Have distance of mars is from the sun so our mars from the sun it is 1 .52 times of distance of earth from the sun and we have the diameter of the diameter of the mars it is equals to 0 .532 times of radius of the earth okay so we have to calculate the intensity of the solar radiation on the mars so we have to calculate i am here so we know that intensity at the earth it is equals to 1368 watt per meter square so power due to the sun will be same for the mars and earth so we can write that i at mars so intensity at mars multiplied by 4 pi rms square this will be equals to ie multiplied by 4 pi res square okay so from here after rearranging we get i m equals to ie modelled by res divided by rms whole square.
01:03
So substituting values, so we get intensity at earth, it is 1368, but applied by res divided by rms, which is this value.
01:15
So 1 .52 of res, okay, and whole square.
01:19
So from here after solving, we get intensity of solar radiation at mars.
01:23
It will be equals to 592 watt per meter square.
01:27
So, this becomes the answer for the part a of the problem.
01:31
Now, moving to the part b in which we have to calculate, we have to calculate the temperature on the surface of mars.
01:40
So we have to calculate temperature...