00:01
So we will be assuming that the mean for unionized nurses is equal to that of non -union, and alternately that the unionized mean is higher than the non -union.
00:15
And we have a sample size of, for the unionized nurses, we have a sample size of 40, and for the non -unionized, we have a sample size of 45.
00:29
So close to the same, but that's, you don't have to have the same.
00:33
And the first mean is $20 .75 an hour.
00:36
And the second mean has a $19 .80.
00:41
So it looks lower, but is it significantly lower with that sample size.
00:45
And that first standard deviation is $2 .25.
00:48
And the second standard deviation is $1 .90.
00:52
So both sample sizes are sufficiently large.
00:55
They're both greater than are equal to 30.
00:57
So we can use a z value.
00:59
We are doing a one -tale test.
01:01
And so let's find with a significance level of 2 % that upper tail of putting all 0 .02 here, we would be rejecting the null if our z value is higher than in that critical value with 2 % in the upper tail is 2 .054, according to my table...