00:01
Hello, so here we're working for the company and the company produces a breakfast cereal.
00:05
So we define a random variable x for the weight of the content of the cereal package.
00:10
So here x follows a normal distribution with mu being equal to 20 and sigma being equal to 0 .6.
00:17
So we select the sample of four packages of the breakfast cereal and we denote the sample mean by x bar.
00:23
So in part a, we calculate the standard error of the sample mean weight and we get that sigma sub x bar.
00:30
Is equal to the square root of sigma or sigma over the square of n.
00:34
So that's 0 .6 divided by the square root of four.
00:37
So 0 .6 divided by 2, that's going to give us 0 .3.
00:41
So the standard error of the sample mean weight is going to be 0 .3.
00:47
And then for part b, we compute the probability that on average, the content of the sample weight is fewer than 19 .7 ounces.
00:57
So we want the probability that x bar is less...