00:01
Well, mass of the particle m1 is equal to 1 .99, multiply by 10 to the power minus 26 kilogram and velocity of the particle is u1 and u1 is equal to 0 .50 times the speed of light.
00:28
And mass of the second particle, mass of the second particle is m2, which is equal to one -third of m, so it's m2 equals m divided by 3 kilogram, right? and velocity of the second particle, u2 is equal to minus 0 .50 times the speed of light, right? now, here, m2 is equal to m1 divided by 3, one third of m1.
01:14
Okay.
01:17
Now, let's apply conservation of momentum.
01:21
Well, according to conservation of momentum, p1 plus p2 is equal to p, right? and p1 is gamma 1 times m1 times u.
01:42
1 and p2 is gamma 2 times m 2 times u 2 and p is gamma times capital m times v okay in this problem gamma 1 is equal to gamma 2 since the magnitude of u1 is equal to u2 which is equal to 0 .50 times the speed of light okay, so further we have gamma 1 times m1 times u1 plus gamma 1 again since gamma 2 is equal to gamma 1 and m2 is equal to m1 divided by 3 into minus u1 which is equal to gamma times mass times we...