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Match each of the ellipsoids in Figure 13 with the correct equation: $$\begin{array}{l}{\text { (a) } x^{2}+4 y^{2}+4 z^{2}=16} \\ {\text { (c) } 4 x^{2}+4 y^{2}+z^{2}=16} \quad \text { (b) } 4 x^{2}+y^{2}+4 z^{2}=16\end{array}$$

$\mathrm{a}-\mathrm{b}$$\mathrm{b}-\mathrm{c}$$\mathrm{c}-\mathrm{a}$

Calculus 3

Chapter 12

VECTOR GEOMETRY

Section 6

A Survey of Quadric Surfaces

Vectors

Vector Calculus

Missouri State University

University of Michigan - Ann Arbor

University of Nottingham

Idaho State University

Lectures

02:56

In mathematics, a vector (…

06:36

06:37

Sketch the surfaces in Exe…

03:09

Fill in each blank with th…

01:27

Complete each equation.

04:11

Solve each system.$$\b…

03:05

Sketch the surfacesELL…

00:22

Fill in each box with the …

02:38

$16 x^{2}+16 y^{2}+16 x-24…

04:36

Solve each system by the m…

02:21

03:56

in discussion here were given the part I we have the X Square plus four one squared plus for the square ecology 16. Now notice that if we try Thio, divide everything here by the 16 they were getting culture X off far square plus why over the Jews square plus the virtues square equal to one and understand this one will be the longest And the major access here is on the expenses they found. The answer for this question here will be, uh we correspond to Indupa. Be here on the graph now for the p were given the equation off the far x square plus why square blast for the square equal to 16 something and we divide everything by the 16 again X over two square plus why over four square plus the hour to square equal to one and then doesn't means that the major access here is on the why exist they found the right graph on this one will be the graph of the sea. And now from the third one we have the for X square plus four White square blessed this quite equal to 16 and we divide everything by the 16, Mr Agendas and will be will be X over except with two square plus. Why over two square plus z over four square, equal to one. Therefore, from here we can conclude that the major access is, um no, the excess here. And therefore the answer for this one will be the part I

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$$4 x^{…

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