00:03
This is the answer to chapter 13, problem number 28 from the smith organic chemistry textbook.
00:10
And so this problem is giving us three molecules and three mass specs and asking us to match each molecule to its mass spectrum.
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And so for a, a is going to be spectrum three.
00:29
And we can identify that because we know that it should have two molecular ion peaks or an m of peak and an m plus two peak.
00:42
And then so the same can be said of b, which contains a chlorine.
00:50
So when we're looking at molecule a, we can eliminate spectrum number two because it does not show two.
00:59
Molecular ion peaks or an m and an m plus two peak.
01:04
But we cannot eliminate one, you know, we can't differentiate between one and three until we look at the ratio of those peaks.
01:14
So remember that bromine is going to give you a peak ratio of one to one for your m to your m plus two.
01:24
Chlorine instead is going to give you a ratio of three to one...