Question
Match the followingTable-1 Table-2(A) time period of an earth(P) Independent of mass of Satellite in circular orbit $\quad$ satellite(B) Orbital velocity of satellite(Q) independent of radius of orbit(C) Mechanical energy(R) independent of mass of earth(S) none
Step 1
From this formula, we can see that the time period is independent of the mass of the satellite. Therefore, we can match (A) with (P). Show more…
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Match the following Table-1 $\quad$ Table-2 (A) kinetic energy (P) $[(-\mathrm{GMm}) /(2 \mathrm{r})]$ (B) Potential energy (Q) $\sqrt{(\mathrm{GM} / \mathrm{r})}$ (C) Total energy (R) - [(GMm) / r] (D) orbital velocity (S) $[(\mathrm{GMm}) /(2 \mathrm{r})]$ Copyright (O StemEZ.com. All rights reserved.
The time period of an earth satellite in circular orbit is independent of (A) the mass of the satellite. (B) radius of its orbit. (C) both the mass and radius of the orbit. (D) neither the mass of the satellite nor the radius of its orbit.
The period of a satellite in a circular orbit around a planet is independent of, (A) the mass of the planet. (B) the radius of the planet. (C) the mass of the satellite. (D) all of three parameters $a, b$ and $c$.
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