00:01
For this question, we just verify this term by term.
00:05
For example, a.
00:08
So if equals to 1 plus 2x to the 1 .5.
00:14
Now we take derivative twice.
00:19
So this should be 1 plus 2x to the minus 1 .5.
00:23
And the double prime will be minus 1 plus 2x to the minus 3 half.
00:30
Then plug in the center.
00:31
So if 0 equals 1, f prime 0 equals to 1, f double prime 0 equals to minus 1, that means p2x equals to 1 plus x minus 1 1 1 1⁄2 square, which is c, the choice of c.
00:53
So for b, f equals to 1 plus 2x to be minus 1 1 1 1 1 half, f prime is minus 2x to be minus 1 1 1 1�, f prime is minus 2x to be minus 1 1 1 1 1.
01:04
Minus 3 half, f double prime equals to 3 times 1 plus 2x 3 minus 5 half, so f0 equals to 1, f0 0 equals to minus 1, f double prime 0 equals to 3.
01:21
So p2 equals to 1 minus x plus 3 1 1 1 1⁄x square, which means this function is corresponding to the choice of e...