Question
$\mathbf{v}_{1}=\left(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}, \frac{1}{2}\right), \quad \mathbf{v}_{2}=\left(\frac{1}{2}, \frac{1}{2},-\frac{1}{2},-\frac{1}{2}\right)$$\mathbf{v}_{3}=\left(\frac{1}{2},-\frac{1}{2}, \frac{1}{2},-\frac{1}{2}\right)$
Step 1
The inner product of two vectors is calculated as the sum of the products of their corresponding entries. For $\mathbf{v}$ and $\mathbf{v}_{1}$, the inner product is $\frac{1}{2}$. For $\mathbf{v}$ and $\mathbf{v}_{2}$, the inner product is $\frac{1}{2}$. Show more…
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