00:01
In this problem, a horseshoe magnet, and suspended between this horseshoe magnet will be a wire that's carrying some current, or at least is conductive, and we'll be able to apply current to it.
00:18
So let's say this is the north, south ends of our magnets, so this is magnetic field in this region here, pointing from the north to south end of the magnet.
00:30
And then we have some wire suspended horizontally between the north -south pole of the magnets.
00:41
We're told that when a current is passed through this wire, so some current i passed through this wire, it jumps straight up and out of the magnet.
00:54
So that's telling us that there's some force, fb, magnetic force, that acts on that wire, when a current runs through it and forces it out of the magnet.
01:08
Well, we can find out what the strength of the magnet of the magnet itself needs to be in order to have a force powerful enough to shoot the wire up into the air.
01:19
We know that right now the only other forces acting on this wire would be gravity, fg, and the force of gravity on the wire is equal to its mass times acceleration due to gravity.
01:35
So we'll use 15 times 10 to the minus 3 kilograms.
01:45
I want to use our si units here, kilograms, and then multiplied by force of gravity, 9 .8 newtons per kilogram.
01:59
You might also see that as meters per second squared.
02:01
It works out to be the same thing.
02:04
And then we just plug that into our calculator and get that the force, of gravity acting on 0 .147 newtons.
02:19
So that's gravity pulling down on the wire.
02:23
Fb then needs to be greater than that force in order to overcome gravity.
02:33
We know that fb is given by this equation be equals il b sine theta.
02:44
The theta is this angle between the magnetic field and the direction of the current...