00:01
So in the given question we are told that a and b are events such that the probability of a union b is equal to 5 by 6 the probability of a intersection b is equal to 1 by 3 which we can write as 2 by 6 and the probability of b is equal to 1 by 2 right so now we are asked to find what kind of events a and b are so we are asked if a and b option 1 option a gives us the answer as equally likely.
00:53
Option b gives us exhaustive.
00:59
Option c gives us mutually exclusive.
01:07
And we have option d which is the final option that gives us the answer as independent.
01:20
So we are told to choose independent.
01:26
We are told to choose which of these options is the correct option.
01:33
So what we need to check first is we know that p of a union b can be found as p of a plus b minus p of a intersection b.
01:52
Right? so this is the formula that we should know.
01:57
So if that's the case, we can say p of a union b is equal to p of a plus p of b we already know as 1 by 2 and p of a intersection b is given us 1 by 3 or we can write it as 2 by 6.
02:16
Let's write it as 1 by 3.
02:18
And a union b is already given as 5 by 6 right...