Question
$\mathrm{A} \mathrm{K}^{+}$ ion and $\mathrm{a} \mathrm{Cl}^{-}$ ion are directly across from each other on opposite sides of a cell membrane $9.0 \mathrm{nm}$ thick. What is the electric force on the $\mathrm{K}^{+}$ ion due to the $\mathrm{Cl}^{-}$ ion? Ignore the presence of other charges.
Step 1
We know that 1 nanometer is equal to $10^{-9}$ meters. So, the distance $R$ in meters is given by: \[R = 9.0 \, \text{nm} = 9.0 \times 10^{-9} \, \text{m}\] Show more…
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$\mathrm{A} \mathrm{K}^{+}$ ion and a $\mathrm{Cl}^{-}$ ion are directly across from each other on opposite sides of a membrane 9.0 nm thick. What is the electric force on the $\mathrm{K}^{+}$ ion due to the $\mathrm{Cl}^{-}$ ion? Ignore the presence of other charges.
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