Question
$\mathrm{As}, I_{s}=\frac{2}{5} M R_{s}^{2}, I_{h}=\frac{2}{3} M R_{h}^{2}$As $\quad I_{s}=I_{h}$$\therefore \quad \frac{2}{5} M R_{s}^{2}=\frac{2}{3} M R_{h}^{2}$$\therefore$$\frac{R_{s}}{R_{h}}=\frac{\sqrt{5}}{\sqrt{3}}$
Step 1
Step 1: Given that the moment of inertia of the solid sphere $I_{s}$ is $\frac{2}{5} M R_{s}^{2}$ and the moment of inertia of the hollow sphere $I_{h}$ is $\frac{2}{3} M R_{h}^{2}$, and that $I_{s}=I_{h}$, we can set the two equations equal to each Show more…
Show all steps
Your feedback will help us improve your experience
Bhavesh Kumar and 63 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Simplify. $$\sqrt[3]{m}(\sqrt[3]{m^{2}}-\sqrt[3]{m^{5}})$$
Radicals and Rational Exponents
Quotients, Powers, and Rationalizing Denominators
Fill in the blank. $$ \sqrt[4]{m^{3}} \cdot \sqrt[4]{?}=\sqrt[4]{m^{4}}=m $$
Dividing Radicals
Solve. $$5 \sqrt{1-5 h}=4 \sqrt{1-8 h}$$
Solving Radical Equations
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD