CH3 CH2 COOH red PCl2⟶ A alc. KOH⟶ B What is B̅ ? (a) CH3 CH2 CHO (b) ClCH2 CH2 COOH (c) CH3 C

Name: Problem 180, Chapter 12: Objective Chemistry for NEET Vol II
Uploaded: 2022-02-14T23:45:44-08:00
Duration: 1 min 32 s
Channel: Dr. Satish Ingale
Description: CH3 CH2 COOH red PCl2⟶ A alc. KOH⟶ B What is B̅ ? (a) CH3 CH2 CHO (b) ClCH2 CH2 COOH (c) CH3 CH2 COCl (d) CH2=CHCOOH

step 1 Hi everyone. So in this question, they asked. CS3, CH2, CL2. Red phosphorus gives A, alcoholic C

Question

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \underset{\mathrm{red} \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow} \mathrm{A}} \stackrel{\text { alc. } \mathrm{KOH}}{\longrightarrow} \mathrm{B}$ What is $\bar{B} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$ (d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

   $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \underset{\mathrm{red} \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow} \mathrm{A}} \stackrel{\text { alc. } \mathrm{KOH}}{\longrightarrow} \mathrm{B}$
What is $\bar{B} ?$
(a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$
(b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$
(c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$
(d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

Objective Chemistry for NEET Vol II

Pearson Education 2nd Edition

Chapter 12, Problem 180

Instant Answer

Solved by Expert Dr. Satish Ingale

02/14/2022

Step 1

This reaction is a halogenation reaction where the hydrogen atom in the alkyl group is replaced by a halogen atom. The product of this reaction is $\mathrm{CH}_{3} \mathrm{CHCl} \mathrm{COOH}$. Show more…

Show all steps

Thanks for your feedback!

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \underset{\mathrm{red} \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow} \mathrm{A}} \stackrel{\text { alc. } \mathrm{KOH}}{\longrightarrow} \mathrm{B}$ What is $\bar{B} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$ (d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

Play audio

Feedback

Dr. Satish Ingale and 71 other subject Organic Chemistry educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Dehydrohalogenation (E2 Elimination Mechanism)

Dehydrohalogenation is an elimination reaction where a halogen and a hydrogen atom are removed from adjacent carbon atoms, forming a carbon-carbon double bond. When an ?-halogenated carboxylic acid is treated with a base like alcoholic KOH, it undergoes an E2 elimination, leading to the formation of an unsaturated carboxylic acid.

Hell-Volhard-Zelinsky Reaction

This reaction involves the ?-halogenation of carboxylic acids using a halogen in the presence of a catalyst such as red phosphorus. It selectively substitutes a hydrogen at the alpha position (the carbon adjacent to the carboxyl group) with a halogen atom, thus preparing the molecule for further transformations.

Please give Ace some feedback