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$\mathrm{H}_{2}$ is produced by the reaction of 118.5 $\mathrm{mL}$ of a $0.8775-\mathrm{M}$ solution of $\mathrm{H}_{3} \mathrm{PO}_{4}$ according to the followingequation: $2 \mathrm{Cr}+2 \mathrm{H}_{3} \mathrm{PO}_{4} \longrightarrow 3 \mathrm{H}_{2}+2 \mathrm{CrPO}_{4}$

(a)1. Find the number of moles of $\mathrm{H}_{3} \mathrm{PO}_{4}$ using molarity $=\frac{\text { number of moles }}{\text { volume in } \mathrm{L}}$ .2. Using the coefficients of the balanced equation, find the number ofmoles of $\mathrm{H}_{2}$ that reacts with the known amount of $\mathrm{H}_{3} \mathrm{PO}_{4}$3. Find the mass of $\mathrm{H}_{2}$ from the number of moles using its molar mass. (b) $0.1560 \mathrm{mol} \mathrm{H}_{2}, 0.3145 \mathrm{g} \mathrm{H}_{2}$

00:44

Sisi G.

Chemistry 101

Chapter 4

Stoichiometry of Chemical Reactions

Chemical reactions and Stoichiometry

Carleton College

University of Central Florida

University of Maryland - University College

Lectures

02:29

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For the reaction $\mathrm{…

00:55

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01:05

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a. Balance this equation: …

06:56

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00:53

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in question. 46. You provided a balanced chemical reaction. As shown here, you're supposed to outline the steps necessary to determine the moles and mass of H. Two. Given a volume and polarity of phosphoric acid, you'll first convert the mill leaders of phosphoric acid into leaders phosphoric acid. Then convert the leaders phosphoric acid into molds of phosphoric acid. Using the polarity of phosphoric acid, Then when you have moles phosphoric acid, you can use the stock geometry of the balanced chemical reaction to convert the molds phosphoric acid into moles of H two. Then you'll convert the moles of H two into grams of H two by multiplying by the molar mass of H two. So it'll look something like this. 118.5 mL converted to leaders by dividing by 1000. The leaders can then be converted into molds of phosphoric acid by multiplying by the polarity of phosphoric acid, which is provided at 0.8775 Mueller. Then when we have moles, phosphoric acid will convert two moles of hydrogen gas, seeing that it is a 2 to 3 relationship, and this will give us malls of hydrogen gas 0.1560 and then last of all to get the grams Step four, we're going to multiply by the molar mass of age, to which is 2.16 and we get 0.3144 g of H two being produced from the complete reaction of 100 and 18 mL of phosphoric acid at 8775 Mueller.

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