Question
$$\mathscr{L}\{f(t)\}=\int_{0}^{2} 4 e^{-s t} d t=-\left.\frac{4}{s} e^{-s t}\right|_{0} ^{2}=-\frac{4}{s}\left(e^{-2 s}-1\right), \quad s>0$$
Step 1
We are given the Laplace transform of a function f(t) as: $$\mathscr{L}\{f(t)\}=\int_{0}^{2} 4 e^{-s t} d t$$ Show more…
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