00:01
Okay, so here we're given a sloplas transform of 6 times e to the negative 3t minus t squared plus 2 times t minus 8.
00:20
Okay, so there's some algebraic rules we can remember.
00:24
Similar to like integrals, we can, when we have things added and subtracted, we can then just add the laplace transforms of each component.
00:35
So this is equal to the laplace transform of 6 times e to the negative 3t, then minus the transform of t squared, plus the transform of 2t, and then minus transform of 8.
01:04
And so there's some other algebraic things we can do here.
01:09
We can pull out a constant that's being multiplied to the front so we'd get six times the transform of e to the negative 3t if we do that there's nothing to pull out for this second one but for the next two we can follow suit so we pull the two out and then here we'll pull the eight out and just leave a one inside okay so now this is an place where we can actually figure things out a little bit.
01:51
So some rules to remember here that we'll be using is that the transform of e to the a .t.
02:09
Is equal to 1 over s minus a.
02:15
The transform of t to the a is equal to a factorial over s to the power of a plus 1.
02:27
And then lastly, that the transform of 1 is equal to 1 over s...