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Matter deforms when stressed. Stress is defined as: $$ \sigma=F / A $$ where F is the force applied to an object and A is the cross-sectional area that experiences the force. Three stresses are commonly defined: tension stress, which elongate an object; compression stress, which compresses an object; and shear stress, which is the application of scissors-like forces. The deformations produced are called strains. Strains are fractional changes in lengths: $$ \varepsilon=\frac{\Delta \mathrm{L}}{\mathrm{~L}} $$ where $L$ is the original length of the object. Stress and strain are linearly related (over a given range of stresses) by Young's modulus, a material's physical property: $$ Y=\frac{\sigma}{\varepsilon} $$ Table 1 lists some Young's moduli for various materials, as well as their ultimate tension stresses and ultimate compression stresses (the maximum stress that a material can tolerate): $$ \begin{array}{|l|c|c|c|} \hline \text { Material } & \begin{array}{c} \text { Young's } \\ \text { Modulus } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} & \begin{array}{c} \text { Tension } \\ \text { Strength } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} & \begin{array}{c} \text { Compression } \\ \text { Strength } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} \\ \hline \text { Aluminum } & 7 \times 10^{10} & 2 \times 10^8 & 2 \times 10^8 \\ \text { Steel } & 2 \times 10^{11} & 5 \times 10^8 & 5 \times 10^8 \\ \text { Glass } & 7 \times 10^{10} & 5 \times 10^7 & \text { not measured } \\ \text { Brass } & \text { not measured } & 2.5 \times 10^8 & 2.5 \times 10^8 \\ \text { Copper } & 9.65 \times 10^{10} & \text { not measured } & \text { not measured } \\ \text { Concrete } & \text { not measured } & 2 \times 10^6 & 2 \times 10^7 \\ \text { Bone } & 1.6 \times 10^{10} & 1.3 \times 10^8 & 1.7 \times 10^8 \\ \hline \end{array} $$ Table 1 A group of students decide to study the relationship between stress and strain. They do two experiments. Experiment 1 A 5-meter-long thin steel wire is hung vertically. The wire has a cross-sectional area of $7.85 \times 10^{-7} \mathrm{~m}^2$. A $10-\mathrm{N}$ weight is hung at the lower end. The position of the lower end of the wire is read on a scale. As more load is added to the wire, the students record their data (Table 2). $$ \begin{array}{|c|c|} \hline \text { After Load (N) } & \text { Scale Reading (cm) } \\ \hline 0 & 4.000 \\ 10 & 4.032 \\ 20 & 4.064 \\ 30 & 4.096 \\ 40 & 4.128 \\ 50 & 4.160 \\ 60 & 4.192 \\ 70 & 4.224 \\ \hline \end{array} $$ Table 2 Experiment 2 Students observe the mechanical properties of thin rods of equal size, constructed from either concrete, brass, or steel. The rods either support loads at their middle sections when oriented horizontally, or loads at their upper end when oriented vertically. What is the maximum strain of the wire in Experiment 1? A. $4.48 \times 10^{-4}$ B. $0.064 \times 10^{-2}$ C. 0.032 D. 0.224

   Matter deforms when stressed. Stress is defined as:

$$
\sigma=F / A
$$

where F is the force applied to an object and A is the cross-sectional area that experiences the force. Three stresses are commonly defined: tension stress, which elongate an object; compression stress, which compresses an object; and shear stress, which is the application of scissors-like forces.

The deformations produced are called strains. Strains are fractional changes in lengths:

$$
\varepsilon=\frac{\Delta \mathrm{L}}{\mathrm{~L}}
$$

where $L$ is the original length of the object.
Stress and strain are linearly related (over a given range of stresses) by Young's modulus, a material's physical property:

$$
Y=\frac{\sigma}{\varepsilon}
$$


Table 1 lists some Young's moduli for various materials, as well as their ultimate tension stresses and ultimate compression stresses (the maximum stress that a material can tolerate):
$$
\begin{array}{|l|c|c|c|}
\hline \text { Material } & \begin{array}{c}
\text { Young's } \\
\text { Modulus } \\
\left(\mathrm{N} / \mathrm{m}^2\right)
\end{array} & \begin{array}{c}
\text { Tension } \\
\text { Strength } \\
\left(\mathrm{N} / \mathrm{m}^2\right)
\end{array} & \begin{array}{c}
\text { Compression } \\
\text { Strength } \\
\left(\mathrm{N} / \mathrm{m}^2\right)
\end{array} \\
\hline \text { Aluminum } & 7 \times 10^{10} & 2 \times 10^8 & 2 \times 10^8 \\
\text { Steel } & 2 \times 10^{11} & 5 \times 10^8 & 5 \times 10^8 \\
\text { Glass } & 7 \times 10^{10} & 5 \times 10^7 & \text { not measured } \\
\text { Brass } & \text { not measured } & 2.5 \times 10^8 & 2.5 \times 10^8 \\
\text { Copper } & 9.65 \times 10^{10} & \text { not measured } & \text { not measured } \\
\text { Concrete } & \text { not measured } & 2 \times 10^6 & 2 \times 10^7 \\
\text { Bone } & 1.6 \times 10^{10} & 1.3 \times 10^8 & 1.7 \times 10^8 \\
\hline
\end{array}
$$
Table 1

A group of students decide to study the relationship between stress and strain. They do two experiments.
Experiment 1
A 5-meter-long thin steel wire is hung vertically. The wire has a cross-sectional area of $7.85 \times 10^{-7} \mathrm{~m}^2$. A $10-\mathrm{N}$ weight is hung at the lower end. The position of the lower end of the wire is read on a scale. As more load is added to the wire, the students record their data (Table 2).
$$
\begin{array}{|c|c|}
\hline \text { After Load (N) } & \text { Scale Reading (cm) } \\
\hline 0 & 4.000 \\
10 & 4.032 \\
20 & 4.064 \\
30 & 4.096 \\
40 & 4.128 \\
50 & 4.160 \\
60 & 4.192 \\
70 & 4.224 \\
\hline
\end{array}
$$
Table 2
Experiment 2
Students observe the mechanical properties of thin rods of equal size, constructed from either concrete, brass, or steel. The rods either support loads at their middle sections when oriented horizontally, or loads at their upper end when oriented vertically.

What is the maximum strain of the wire in Experiment 1?
A. $4.48 \times 10^{-4}$
B. $0.064 \times 10^{-2}$
C. 0.032
D. 0.224
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MCAT: The Berkley Review Physics Book II
MCAT: The Berkley Review Physics Book II
kalbaba 1st Edition
Chapter 7, Problem 58 ↓
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Matter deforms when stressed. Stress is defined as: $$ \sigma=F / A $$ where F is the force applied to an object and A is the cross-sectional area that experiences the force. Three stresses are commonly defined: tension stress, which elongate an object; compression stress, which compresses an object; and shear stress, which is the application of scissors-like forces. The deformations produced are called strains. Strains are fractional changes in lengths: $$ \varepsilon=\frac{\Delta \mathrm{L}}{\mathrm{~L}} $$ where $L$ is the original length of the object. Stress and strain are linearly related (over a given range of stresses) by Young's modulus, a material's physical property: $$ Y=\frac{\sigma}{\varepsilon} $$ Table 1 lists some Young's moduli for various materials, as well as their ultimate tension stresses and ultimate compression stresses (the maximum stress that a material can tolerate): $$ \begin{array}{|l|c|c|c|} \hline \text { Material } & \begin{array}{c} \text { Young's } \\ \text { Modulus } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} & \begin{array}{c} \text { Tension } \\ \text { Strength } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} & \begin{array}{c} \text { Compression } \\ \text { Strength } \\ \left(\mathrm{N} / \mathrm{m}^2\right) \end{array} \\ \hline \text { Aluminum } & 7 \times 10^{10} & 2 \times 10^8 & 2 \times 10^8 \\ \text { Steel } & 2 \times 10^{11} & 5 \times 10^8 & 5 \times 10^8 \\ \text { Glass } & 7 \times 10^{10} & 5 \times 10^7 & \text { not measured } \\ \text { Brass } & \text { not measured } & 2.5 \times 10^8 & 2.5 \times 10^8 \\ \text { Copper } & 9.65 \times 10^{10} & \text { not measured } & \text { not measured } \\ \text { Concrete } & \text { not measured } & 2 \times 10^6 & 2 \times 10^7 \\ \text { Bone } & 1.6 \times 10^{10} & 1.3 \times 10^8 & 1.7 \times 10^8 \\ \hline \end{array} $$ Table 1 A group of students decide to study the relationship between stress and strain. They do two experiments. Experiment 1 A 5-meter-long thin steel wire is hung vertically. The wire has a cross-sectional area of $7.85 \times 10^{-7} \mathrm{~m}^2$. A $10-\mathrm{N}$ weight is hung at the lower end. The position of the lower end of the wire is read on a scale. As more load is added to the wire, the students record their data (Table 2). $$ \begin{array}{|c|c|} \hline \text { After Load (N) } & \text { Scale Reading (cm) } \\ \hline 0 & 4.000 \\ 10 & 4.032 \\ 20 & 4.064 \\ 30 & 4.096 \\ 40 & 4.128 \\ 50 & 4.160 \\ 60 & 4.192 \\ 70 & 4.224 \\ \hline \end{array} $$ Table 2 Experiment 2 Students observe the mechanical properties of thin rods of equal size, constructed from either concrete, brass, or steel. The rods either support loads at their middle sections when oriented horizontally, or loads at their upper end when oriented vertically. What is the maximum strain of the wire in Experiment 1? A. $4.48 \times 10^{-4}$ B. $0.064 \times 10^{-2}$ C. 0.032 D. 0.224
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A metal wire $75.0 \mathrm{~cm}$ long and $0.130 \mathrm{~cm}$ in diameter stretches $0.0350 \mathrm{~cm}$ when a load of $8.00 \mathrm{~kg}$ is hung on its end. Find the stress, the strain, and the Young's modulus for the material of the wire. $$ \begin{array}{l} \sigma=\frac{F}{A}=\frac{(8.00 \mathrm{~kg})\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)}{\pi\left(6.50 \times 10^{-4} \mathrm{~m}\right)^{2}}=5.91 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}=5.91 \times 10^{7} \mathrm{~Pa} \\ \varepsilon=\frac{\Delta L}{L_{0}}=\frac{0.0350 \mathrm{~cm}}{75.0 \mathrm{~cm}}=4.67 \times 10^{-4} \\ Y=\frac{\sigma}{\varepsilon}=\frac{5.91 \times 10^{7} \mathrm{~Pa}}{4.67 \times 10^{-4}}=1.27 \times 10^{11} \mathrm{~Pa}=127 \mathrm{GPa} \end{array} $$

Schaum’s Outline of College Physics


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Transcript

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0:00 Good day.
00:01 In this question, we will be solving for the stress, strain, and the youse modules of the wire.
00:08 So for the stress, we will be using the stress equals force over area, where force is the product of the mass given times the gravitational acceleration, which is 9 .81 meters per second squared.
00:27 For the area, we will be using the area of circle which is pi r squared, and the radius here is half of 1 .130 centimeters, which is 0 .065 centimeters.
00:46 Converting to meters, we have 100 centimeters is 1 meter.
00:54 Therefore, our stress is equal to 5 .91 times 10 to the power of 7 newton per meter squared, or 5 .91 times 10 to the power of 7 pascal.
01:13 Since pascal is just equal to newton per meter squared.
01:18 Next, solving for the strain, we have the change in length...
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