Question
Maximizing Revenue Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is $p$ dollars, the revenue $R$ (in dollars) is$$R(p)=-4 p^{2}+4000 p$$What unit price $p$ maximizes revenue? What is the maximum revenue?
Step 1
This can be found by finding the x-value of the vertex of the quadratic function. The x-value of the vertex (which we'll call $p$ since $p$ is the variable in the function) can be found by using the formula $-\frac{b}{2a}$. Show more…
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Maximizing Revenue Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is $p$ dollars, the revenue $R($ in dollars) is $$ R(p)=-4 p^{2}+4000 p $$ What unit price should be established for the dryer to maximize revenue? What is the maximum revenue?
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Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is $p$ dollars, the revenue $R$ (in dollars) is $$ R(p)=-4 p^{2}+4000 p $$ What unit price $p$ maximizes revenue? What is the maximum revenue?
Suppose that the manufacturer of a gas clothes dryer has found that, when the unit price is $p$ dollars, the revenue $R$ (in dollars) is $$R(p)=-4 p^{2}+4000 p$$ What unit price should be established for the dryer to maximize revenue? What is the maximum revenue?
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