00:01
Here, given demand equation between price and quantity is p equal to minus of x by 3 plus 100.
00:09
Now in first part we have to find revenue as function of x.
00:14
Now we know that revenue will be equal to price multiplied with quantity.
00:21
So our revenue will be equal to minus of x squared by 3 plus 100 times x.
00:30
Now, in second part, we have to find domain of revenue.
00:35
We know that the venue cannot be negative, so our r will be greater than equal to 0.
00:42
So we can write minus o x squared by 3 plus 100 times x will be greater than equal to 0.
00:52
We can rewrite this equation as x square by 3 is less than equal to 100 times x.
01:01
From here we can write x is less than equal to 300.
01:07
Now we know that quantity cannot be negative, so x will be greater than equal to 0.
01:13
Now in next part we have to find revenue for 100 units sold.
01:20
So we can say that here value of x will be equal to 100 which is given, so we have to find revenue for x equal to 100.
01:28
Revenue will be minus of 100 squared by 3 plus 100 square...