00:01
Okay, so the first part of this question is asking us to find the, it's asking us to find the maximum minimum value of the function by using, so you can use a calculator or you can use a graphical device.
00:16
I'll just use my calculator.
00:19
I'm using the cassio fx 891 or 991 ex at the moment.
00:27
Right, so if you just type the equation into the, it's going to be different for every calculator, so it's hard for me to help you along with this right now but just ask your tutor or your teacher how to do this on your particular device maybe that you need to get a new device i'm not sure really but it's always good investing in a cap rate that can do this sort of thing so if you put this into your calculator what i get as a minimum value is i get minus four point and it asks us to round to two decimal places i get minus 4 .0 1 to 2 decimal places.
01:10
Okay.
01:11
And then part b actually to find the minimum minimum or maximum value without doing that.
01:18
And okay, so the way i'm going to find the maximum or minimum values, i'm actually going to use the maximum or minimum value equation to find the x coordinate as a vertex and then i'm going to sub that in.
01:28
So the x coordinate of the vertex is minus b over to a here.
01:34
And that's going to equal minus 1 .79 over two times by one so that's just over two and i put that into my calculator i don't want to be rounding at all here because that'll that i'll reduce the accuracy of my answer i get just minus 179 over 200 and i can just keep it as that for the moment and then i'll sub that back into the equation and i'll see what that gives me.
02:11
So minus 179 over 200 all squared plus 1 .79 times by 179 over 200 minus 3 .21...