00:02
Right.
00:02
In this problem, we need to start out by writing our balanced equation.
00:07
They tell us that water is being broken down into hydrogen and oxygen.
00:15
So writing my balanced equation gives me 2h2o, breaks into 2h2 plus o2.
00:26
I want to know how many grams of water are needed to produce 23 .9 liters of hydrogen.
00:40
And it's at 28 degrees celsius and 728 tor.
00:50
I'm going to go ahead right away and convert my temperature to kelvin by adding 273, and that gives me 301 kelvin.
01:03
To solve this problem, i'm going to need to do stochialometry.
01:07
However, before i can do that, i need to know how many moles of hydrogen i have.
01:12
I cannot simply use 22 .4 in this problem because i am not.
01:18
At standard temperature and pressure.
01:20
To determine how many moles i have, i'm going to use the ideal gas equation, and i have rearranged it to solve four number of moles.
01:28
So that's going to be pv over rt.
01:34
So let's go ahead and plug in these values to figure out how many moles of hydrogen i have.
01:41
The pressure is 728 or.
01:49
The volume that is given in the problem is 23 .9 liters.
01:59
The r that i'm going to select is the universal gas constant that has tor as one of the units...