Question
Measurements show that $1.0 \mathrm{g}$ of iron (Fe) contains $1.1 \times 10^{22}$ Fe atoms. How many Fe atoms are in $4.9 \mathrm{g}$ of $\mathrm{Fe}$, which is the total amount of iron in the body of an average adult?
Step 1
We know that 1.0 g of iron contains $1.1 \times 10^{22}$ Fe atoms. We also know that the total amount of iron in the body of an average adult is 4.9 g. Show more…
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Measurements show that $1.0 \mathrm{g}$ of iron (Fe) contains $1.1 \times 10^{22} \mathrm{Fe}$ atoms. How many Fe atoms are in $4.9 \mathrm{g}$ of Fe, which is the total amount of iron in the body of an average adult?
What number of Fe atoms and what amount (moles) of Fe atoms are in 500.0 g of iron?
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