Mesitylene is a liquid hydrocarbon. If 0.115 g of the compound is burned in pure O2 to give 0.3

step 1 Hi there. Welcome to problem number 89. In problem number 89, we have a hydrocarbon. A hydrocarb

Mesitylene is a liquid hydrocarbon. If 0.115 g of the...

Mesitylene is a liquid hydrocarbon. If $0.115 \mathrm{~g}$ of the compound is burned in pure $\mathrm{O}_{2}$ to give $0.379 \mathrm{~g} \mathrm{CO}_{2}$ and $0.1035 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}$, what is the empirical formula of the compound?

Key Concepts

Empirical Formula Determination

Determining the empirical formula means finding the simplest whole-number ratio of atoms in a compound. After calculating the moles of each element present from the combustion products, these values are compared and simplified to achieve the lowest whole-number ratio. This process is critical in establishing the basic composition of a compound.

Stoichiometric Calculations

Stoichiometric calculations are essential for converting between different units and substances using balanced chemical relationships. In the context of combustion analysis, they enable the conversion of masses of CO2 and H2O to moles of carbon and hydrogen, thereby linking the measured data to the chemical formula of the original compound.

Combustion Analysis

Combustion analysis involves burning a compound in oxygen to convert its carbon and hydrogen into CO2 and H2O, respectively. The amounts of these products are then used to determine the amount of carbon and hydrogen in the original compound through mass-to-mole conversions. This method is a fundamental analytical technique in determining the empirical formula of organic compounds.