m=(m0)/(√(1-β^2)) For β∼1, (m)/(m0)=(1)/(√(2(1-β)))=(1)/(√(2 η))

Name: Problem 368, Chapter 1: Solutions to I.E. Irodov's problems in general physics
Uploaded: 2021-08-20T09:24:47-08:00
Duration: 1 min 4 s
Channel: Narayan Hari
Description: m=(m0)/(√(1-β^2)) For β∼1, (m)/(m0)=(1)/(√(2(1-β)))=(1)/(√(2 η))

Question

m=(m0)/(√(1-β^2)) For   β∼1, (m)/(m0)=(1)/(√(2(1-β)))=(1)/(√(2 η))

Narayan Hari · Accepted Answer

step 1 In this problem, I can write the value of m is equal to m0 by under root 1 minus beta square. So

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