Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉Join our Discord! Numerade Educator ### Problem 34 Easy Difficulty # Microwaves of wavelength 5.00$\mathrm{cm}$enter a long, narrow window in a building that is otherwise essentially opaque to the incoming waves. If the window is 36.0$\mathrm{cm}$wide, what is the distance from the central maximum to the first-order minimum along a wall 6.50$\mathrm{m}$from the window? ### Answer ##$90.3 \mathrm{~cm}\$

#### Topics

Electromagnetic Waves

Wave Optics

### Discussion

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### Video Transcript

for our question were asked to find the distance from the central maximum to the first order minimum along the wall. Uh, that is a distant L of 6.5 meters from the window. The wavelength of the light is lambda, and it's equal to uh is equal to five centimeters and the window. The wit is equal to 36 centimeters. So to find the distance, then why we simply have to use the equation, uh, Lambda Times out over a so plug in our values for Lambda and L and A. But make sure that you use, um the same unit. So lamda and air both in centimeters so you can put L and Centimeters so 6.5 meters is equal to 650 centimeters. So playing in all these values and your expression, we find that this is equal to 90.3 centimeters. Making box system is their solution to our question.