💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

Like

Report

Get the answer to your homework problem.

Try Numerade Free for 7 Days

mmh An 81-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is 0.49. (a) What is the magnitude of the frictional force? (b) If the player comesto rest after 1.6 s, what was his initial velocity?

390 $\mathrm{N}$ 7.7 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 4

Forces and Newton’s Laws of Motion

Newton's Laws of Motion

Applying Newton's Laws

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

McMaster University

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

01:12

A baseball player with mas…

03:16

After hitting a long fly b…

02:10

A 70 -kg base runner begin…

03:52

(II) A 144-g baseball movi…

02:41

(II) A 144 -g baseball mov…

17:21

A 1.8 -kg block slides on …

02:20

A baseball of mass $m$ and…

03:33

$\bullet$ A 61 kg skier on…

05:58

A skier with a mass of $63…

01:29

A 63 -kg skier coasts up a…

in this question. There are three forces acting on the player. The weight forced the normal force, alerted by the ground and the frictional force exerted by the ground too. And in the first item, we have to calculate what is the magnitude off. The frictional force knows that the player is already moving. It's sliding on the ground. Therefore, we can calculate the frictional force using the following equation frictional force. In that case, where the player is already moving, he's given by the genetic frictional coefficient times the normal force. But in the situation, the normal force is exactly counterbalanced by the weight force. Therefore, what we have here is that the frictional force Zico student kinetic friction coefficient times The weight force with the weight force is given by the mass off the player times acceleration off gravity. Remember that acceleration of gravity is approximately 9.8 meters per second squared near the surface off the earth. Therefore, the fictional force is given by 0.49 times into one times 9.8, which gives us a frictional force off approximately 300 19 new times. So this is the answer for the first item on the second night and we have the following. The player started his light and then after a time off 1.6 seconds, it comes to rest. So the final velocity is he close to zero? Then what? Waas his initial velocity. To answer that question, we can use the following equation the velocity as a function off time. Is it close to the initial velocity plus the acceleration things that interval of time, then the final velocity is zero. So zero is it close to the initial velocity plus the acceleration times 1.6, which is the time it took for the velocity to become zero Then the initial velocity is because to minors acceleration times 1.6. Then how can we calculate acceleration? We can use Newton's second law for that you don't Second Law tells us that that force is the coast. The mass times acceleration. We we were applying Newton's second law over the horizontal axis, which I choose to be pointing to the right. Then the net force on that access is the frictional force. We just pointing to the left So miners fictional force is there close to the mass off that player times its acceleration then minus 390 is he goes to 81 times acceleration finally minus 390. Divided by a 21 is the acceleration off the player. Then the initial velocity is eco's too. 390 times 1.6 divided by 8 to 1. What happened to the minus sign? Well, there is a minor sign here and the minus sign here. So minus sign times a minus sign is a plus sign. This is why the minus sign Don't appear here and then the initial velocity is approximately 7.7 meters per second and this is the answer for the second item.

Numerade Educator

In mathematics, a proof is a sequence of statements given to explain how a c…

In mathematics, algebra is one of the broad parts of mathematics, together w…

A baseball player with mass $m=79$ kg, sliding into second base, is retarded…

After hitting a long fly ball that goes over the right fielder'shead an…

A 70 -kg base runner begins his slide into second base when he is moving at …

(II) A 144-g baseball moving 28.0 m/s strikes a stationary 5.25-kg brick res…

(II) A 144 -g baseball moving 28.0 $\mathrm{m} / \mathrm{s}$ strikes a stati…

A 1.8 -kg block slides on a horizontal surface with a speed of $v=0.80 \math…

A baseball of mass $m$ and initial speed $v$ strikes a catcher's mitt.<…

$\bullet$ A 61 kg skier on level snow coasts 184 m to a stop froma speed…

A skier with a mass of $63 \mathrm{kg}$ starts from rest and skis down an ic…

A 63 -kg skier coasts up a snow-covered hill that makes an angle of $25^{\ci…