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mmh The speed of a bobsled is increasing because it has an acceleration of 2.4 $\mathrm{m} / \mathrm{s}^{2}$ . At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 $\mathrm{N}$ . The combined mass of the bobsled and its riders is 270 $\mathrm{kg} .$ (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

$1100 \mathrm{N}$

650 $\mathrm{N}$

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Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

McMaster University

to solve this question, we have to apply Newton's second law for that. Have you used the following reference frame horizontal axis pointing to the right that I'll call acts. Then, using Newton's second law, we get the following, and that force is equal to the Mass. So the total mass off this lead times its acceleration, the net force. It's been posed by true forces. They're resistant forces on the force f. There's propelling the bulbs, lad forward. Then the net force is F minus. F our and this is equals to the total mass off the bobsled times its acceleration, the magnitude off The propelling force is then given by F R plus to Thomas Times, its acceleration plugging in the values that were given. We have 450 plus 270 times true 2700.4. And these results in a propelling force off approximately 1000 and 100 Newtons. The magnitude off the net force that is acting on the bobsled is given either by f minus f our so you can calculate it using this side of the equation, or you can use the total mass times acceleration you choose to use the total mass times acceleration. So you straight Wardley in that force is equals to 270 times a true 2700.4, resulting in a net force off approximately 650 Newtons. And these is there and start to this question.

Brazilian Center for Research in Physics