Molar conductivity of a solution of an electrolyte $A B_{3}$ is $150 \mathrm{Scm}^{2} \mathrm{~mol}^{-1}$. If it ionises as $\mathrm{AB}_{3} \longrightarrow A^{3+}+3 B^{-}$, its equivalent conductivity will be :
(a) $150\left(\right.$ in $\mathrm{Scm}^{2} \mathrm{eq}^{-1}$ )
(b) 75 (in $\mathrm{Scm}^{2} \mathrm{eq}^{-1}$ )
(c) 50 (in $\mathrm{Scm}^{2} \mathrm{eq}^{-1}$ )
(d) 80 (in $\mathrm{Scm}^{2} \mathrm{eq}^{-1}$ )