00:01
So what we're looking to do here is to find the moment of inertia of this circle given with the equation x squared plus y squared is equal a squared.
00:13
And we know that the density of this circle, this thin hoop, is delta.
00:19
So the first thing that i'm going to do is to just draw a circle to show what we're working with here to find the density of.
00:28
And so we know that based off of the form of the equation, we have a circle, and we also know that it has a radius of a.
00:37
So all along these axes in the x, y plane, we're dealing with the circle of radius a.
00:47
And in order to find the moment of inertia here, which is what we're looking for, we use the point mass moment of inertia.
00:58
Formula but we're going to adjust it so that we're doing it for each point along the circle so we're adding up the point mass moment of inertia in order to find the point mass moment of inertia or in order to find the moment of inertia for the entire circle and so this formula that we're going to be using here is based off of the point mass which is m squared or sorry m times r squared where m is mass and r is radius.
01:36
So in order to find the mass, looking at what's given, we know that the circle has a constant density of delta.
01:45
And so we can find the mass of the whole hoop, the whole circle by integrating the density along the curve.
01:56
So we're going to do delta ds along the curve c.
02:01
And thus we're like adding up all the densities at each point on the curve.
02:07
And so that will give us our mass, which is equal to m.
02:13
And then in order to find the radius, we look at the equation of the circle that we were given above.
02:19
And we know that the general equation of a circle is x squared plus y squared is equal to r squared, which in this case is equal to a squared...