00:01
We have that the rate of continuous money flow starts at $1 ,000 per year, and it will increase exponentially at a rate of 5 % per year for four years.
00:19
And what we want to do is find the present value and the accumulated if interest earned is 3 .5%, which is going to be compounded continued.
00:29
So to find accumulated, we need to find present value.
00:34
So let's first go ahead and find our present value.
00:39
So recall that present value is equal to 0 to t, where capital t is going to be our time interval, with the function f of t, which tells us our rate of money, which will bring you in per year, multiplied by e to the negative r, little t, t, where this little r is supposed to be r.
01:16
Rate our interests that we're getting.
01:20
So we're told that the money flow, so f of t is described by this part here.
01:32
So it starts at $1 ,000 and then exponentially increases at 5 % per, year.
01:39
So, because this is telling us is that f of t is going to be, so it starts at 1000 and then it's going to be multiplied by e since it's exponentially increasing times 0 .05 t.
02:05
So this here will describe our value because when we plug in one into this it would be 1 ,000 times e to the 0 .0 5t which would be just that much more times a thousand and so we have that so we can go ahead and plug this in to our present value equation so we have zero time interval is going to be 4 so that's our capital t f of t like we said over there is going to be 1 ,000 e through 0 .0.
02:51
Times e to the negative so our r is this 3 .5 % here so this is our little r so this would be 0 .00 so 0 .035 d t and what we are going to need to do now oh i'm and i drop that t right there.
03:33
So i'm going to first factor out from 1 ,000.
03:35
Still have my integral from 0 to 4.
03:38
And then i'm going to combine these two exponentials, and that will give 0 .25 minus 0 .035.
03:50
So this will be e to the 0 .015t, dt.
04:01
And you might recall to enterrate this is going to be e to 0 .015t divided by its new power, which is 0 .015...