00:01
In this case, we're told that we now exert a 630 newton force on this rope, and we have the same engine block here, and we want to figure out what these two angles are.
00:16
So we draw our free body diagram.
00:21
Again, we have the weight of the engine, and that also the weight of the engine passes through the pulley and is in this part of the rope.
00:30
2.
00:31
So that's the weight of the engine and we have our force that we're now exerting 630 newtons.
00:39
So we can do force balances on our pulley.
00:44
In the x direction we have minus f cosine theta 2, okay the x component of this force, plus mg the weight of the engine times cosine of theta 1 so the component of that force in this direction.
01:04
This has no component in the x direction.
01:08
In the y direction we have the y component of this force which is f sign of theta and then we have the y component of this force which is mg sine of theta 1 and then we have minus mg which i've just lumped into here and pull out the weight of the engine.
01:30
So now we have we have two equations and two unknowns and we need to solve those.
01:36
And one thing we can do is take, put this guy on the other side here and then square both sides.
01:43
So that gives us f squared, cosine squared or theta 2 equals m g squared cosine squared of theta 1.
01:53
We can then take this equation, we can then take this equation, and square it, we'll move this on the other side and then square both sides...