00:04
So here we need to use the heat transfer equation to determine the heat change of water.
00:09
So we have q for the heat.
00:11
It's equal to m, the mass, the specific heat capacity multiplied by the change in temperature.
00:18
While we calculate delta t is 11 .8 degrees celsius.
00:22
And then we plug all of our values in to get 2 .496 joules.
00:28
And that is the energy absorbed by the water.
00:31
And so the energy absorbed by the water is equal in magnitude, but it is opposite in sign to the energy that is released by the hot metal.
00:39
So this is because the increase in water heat, we have a plus q, comes from the decrease in the metal heat minus q.
00:49
And so therefore we can use the same equation again, where we're looking to solve for q...