00:04
In this problem, the battery life in hours of brand x batteries are given, which we have denoted by x.
00:17
It is asked to find the mean and standard deviation for the sample of brand x batteries.
00:26
To find the mean and standard deviation, we will require one more column of x square.
00:32
So we will find square of each x value.
00:39
Square of 15 is 225.
00:46
Square of 18 is 324.
00:54
19 square is 361.
01:02
23 square is 529.
01:10
25 square is 625.
01:20
Again 625.
01:26
Now 28 square is 784.
01:35
30 square is 900, 34 square is 1156 and 38 square is 1 444.
02:01
So in this way we have found the square values for each x value.
02:06
Now we will take the sum of all x values as well as the sum of all x square values.
02:14
The sum of all x values is 255.
02:24
Whereas the sum of all x square values is 6 ,973.
02:40
It is 6973.
02:45
So we have found our summation x, that is the sum of all x values, is equal to 255, and summation x squared, that is the sum of all x square values, is equal to 6973.
03:08
Now, first we will find the mean.
03:13
We know the formula for mean is x bar equal to summation x divided by n.
03:27
So this is equal to our summation x is 255 divided by n...