Most stable carbanion is (a) (CH3)3 C^- (b) C6 H5 CH2^- (c) (CH3)2 CH^- (d) CH3 CH2^-

Name: Problem 40, Chapter 24: A Complete Resource Book in Chemistry for JEE Main 2019
Uploaded: 2021-09-16T08:46:48-08:00
Duration: 1 min 6 s
Channel: Hitendra Singh
Description: Most stable carbanion is (a) (CH3)3 C^- (b) C6 H5 CH2^- (c) (CH3)2 CH^- (d) CH3 CH2^-

step 1 So we are going to discuss which of the following carbon is the most stable. So correct option i

Most stable carbanion is (a) (CH3)3 C^- (b) C6 H5 CH2^- (c)...

Most stable carbanion is
(a) $\left(\mathrm{CH}_3\right)_3 \mathrm{C}^{-}$
(b) $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2^{-}$
(c) $\left(\mathrm{CH}_3\right)_2 \mathrm{CH}^{-}$
(d) $\mathrm{CH}_3 \mathrm{CH}_2^{-}$

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Key Concepts

Inductive Effects

Inductive effects involve the transmission of electron density through sigma bonds. Substituents that withdraw electron density can help stabilize a nearby negative charge by reducing electron-electron repulsion, whereas electron-donating groups can have a destabilizing effect.

Hyperconjugation

Hyperconjugation provides additional stabilization for carbanions by allowing the overlap of adjacent sigma bonds with an empty or partially occupied orbital on the carbanionic center. Although its effect is usually less significant than resonance stabilization, it still plays a role in determining overall stability.

Carbanion Stability

The stability of carbanions depends on the ability to delocalize or disperse the negative charge over a larger area. Factors such as resonance stabilization, inductive effects, and hyperconjugation contribute significantly to how well the negative charge is stabilized on the carbon atom.

Resonance Stabilization

Resonance stabilization occurs when the negative charge on the carbanion can be delocalized over an adjacent pi system or aromatic ring. This delocalization reduces the electron density on any one carbon atom, leading to enhanced stability of the carbanion.

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