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All right, guys, we're doing problem 58 of chapter 8 in chemistry, central science.
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So, mothballs are composed of naphthalene, c10h8, a molecule that consists of six membered rings of carbon fused along an edge.
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You can see that here.
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So draw the resin and structures of naphthalene.
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How many are there? there are three.
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They're shown here.
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Do you expect the cc bond less in the molecule to be similar to the cc single bonds, cc double bonds, or an intermediate between cc single and cc double bonds? like in benzene, the cc bonds and napoline have an intermediate path due to the resonance structure.
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So they're between the normal cc bond and the cc double bond due the currents of pi conjugation.
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So what you see throughout all these cc interactions, these actually have single bonds with partial double bond character.
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That's a consequence of aromaticity.
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So see, not all the cc bond lace and napling are equivalent.
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Based on your resonance, how many cc bonds in the molecule do you expect to be shorter than the other? so let's look at our molecules.
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So let's see what we're changing.
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Let's see our resident structure.
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So let's compare resident structures.
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So in these two resident structures, we're changing between, we're not affecting the carbons on the left.
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We're affecting the carbons on the right.
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We're shifting it and moving these bonds around.
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Now for here, we're moving.
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Now for this structure, we are directly manipulated.
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Manipulating the bonds...