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Multiple-Concept Example 4 provides useful background for this problem. A diver runs horizontally with a speed of 1.20 m/s off a platform that is 10.0 m above the water. What is his speed just before striking the water?

$v=14.05 \mathrm{m} \cdot \mathrm{s}^{-1}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two Dimensions

Motion in 2d or 3d

University of Michigan - Ann Arbor

University of Sheffield

University of Winnipeg

Lectures

04:01

2D kinematics is the study of the movement of an object in two dimensions, usually in a Cartesian coordinate system. The study of the movement of an object in only one dimension is called 1D kinematics. The study of the movement of an object in three dimensions is called 3D kinematics.

10:12

A vector is a mathematical entity that has a magnitude (or length) and direction. The vector is represented by a line segment with a definite beginning, direction, and magnitude. Vectors are added by adding their respective components, and multiplied by a scalar (or a number) to scale the vector.

02:25

Multiple-Concept Example 4…

03:23

Consult Multiple-Concept E…

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05:40

Consult Conceptual Example…

07:00

A rock climber stands on t…

09:05

02:04

Suppose the slope of a bea…

01:30

An athlete crosses a 25-m-…

09:51

REFERRING TO EXAMPLE 4-11 …

01:34

A water balloon is thrown …

00:56

In the previous problem, f…

So the question states that a diver runs off the edge of a cliff at 1.2 meters per second in the horizontal direction, and the cliff is 10 meters high. And we're trying to find what the divers velocity is right when he hits the water. So this question is actually pretty simple to solve. We can look at what the velocity vector of the diver is right before he hits the water and it all looks something like this. So he's going toe, have a horizontal component for the velocity as well as a vertical component going into the water to say this is the water here. And then this is his total, uh, velocity here. So this is a piece of X and visa. Why? So we know Visa Vex must be equal to 1.2 meters per second because its projectile motion and when he runs off the top of the cliff, he's only moving in the horizontal direction. So there's no acceleration in the horizontal direction, so the velocity is constant. And now that we know that we need to find what visa, why is that? We confined Capital V here. So to find resupply. We really have all the information we need. We just need to use our Kinnah Matics equations Teoh Sulphur sport to software. So the equation we should use in this case is the one that states that the final velocity squared physical to the initial velocity squared plus two times the acceleration times, the change in displacement. So we know that we're trying to find this final velocity here. This is for the vertical direction and only for the vertical direction. We know that in the vertical direction, it's his initial velocity is zero. So this term will cancel out. And we know what his acceleration is in the vertical direction as well as how far he falls, which is gonna be 10 meters so we can set up. This equation will see that V squared is equal to two times negative 9.8 due to gravity. And his total displacement is negative 10 meters because he followed down 10 meters and so we can solve for of v squared. And what we'll find is that we get the is equal to 14 meters per second. This is in the vertical direction. This will be the supply And now that we know that our visa, Becks and at what? Our visa, Becks, and Visa why is we can sell for Capital V? Because we know that the square root of piece of X squared plus visa why squared should be equal to Capital V and so we can plug in the numbers that we have Emma find that capital fee is equal to 14 0.5 meters per second.

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