00:01
In this problem, we have 10c times 3 5th c squared minus 1 half times c squared plus 1.
00:14
And there are two ways you can solve this.
00:16
You can either multiply the 10c and the 3 5th c squared minus 1 half first and then multiply by c squared plus 1.
00:24
Or you can multiply the two binomials first and then multiply that larger polynomial by 10c.
00:33
But i prefer to multiply straight from left to right, so that's what we're going to do.
00:38
We're going to distribute this 10c to the 3 5th c squared minus 1⁄2nd.
00:45
And that's going to give us 10c times 3 5th c squared plus 10c.
00:55
Times negative 1 half and that's still times our c squared plus 1.
01:04
And so we get 10c times 3 .5c squared gives us 30 over 5 c to the third.
01:15
And 10c times negative 1 half gives us a minus 10 over 2c.
01:24
And that's times our c squared plus 1...