Question
Multiply and, if possible, simplify.$$\frac{a^{3}-b^{3}}{3 a^{2}+9 a b+6 b^{2}} \cdot \frac{a^{2}+2 a b+b^{2}}{a^{2}-b^{2}}$$
Step 1
We can factor them using the formula \(a^2 - b^2 = (a-b)(a+b)\). So, we have: $$ \frac{(a-b)(a^2+ab+b^2)}{3a^2+9ab+6b^2} \cdot \frac{a^2+2ab+b^2}{(a-b)(a+b)} $$ Show more…
Show all steps
Your feedback will help us improve your experience
Ankit Gupta and 77 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Multiply, and then simplify, if possible. See Example 3. $$ \frac{a^{2}+3 a b+2 b^{2}}{a^{2}-3 a b-4 b^{2}} \cdot \frac{a^{2}-4 a b}{a b^{2}+2 b^{3}} $$
Rational Expressions and Equations
Multiplying and Dividing Rational Expressions
Simplify the expression. $$\frac{2 a^{2}-3 a b-9 b^{2}}{2 a b^{2}+3 b^{3}}$$
Preliminaries
Precalculus Review II
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD