Question
Multiply and, if possible, simplify.$$\frac{x^{2}-6 x+9}{12-4 x} \cdot \frac{x^{6}-9 x^{4}}{x^{3}-3 x^{2}}$$
Step 1
The expression $x^{2}-6x+9$ can be factorized as $(x-3)^{2}$, $x^{6}-9x^{4}$ can be factorized as $x^{4}(x^{2}-9)$, $12-4x$ can be factorized as $-4(3-x)$, and $x^{3}-3x^{2}$ can be factorized as $x^{2}(x-3)$. So, the given expression Show more…
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