For the first fraction, we can factor out 4 from the numerator to get $4(3x-5)$ and for the second fraction, we can factor out 3 from the denominator to get $3(3x-5)$.
So, the expression becomes:
$$
\frac{4(3x-5)}{5x} \cdot \frac{6}{3(3x-5)}
$$
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