So we can rewrite the expression as:
$$
\frac{(a-b)^{3}}{(a-b)(a^2 + ab + b^2)} \cdot \frac{(a-b)(a+b)}{(a-b)^{2}}
$$
Now, we can cancel out the common factors in the numerators and denominators:
$$
\frac{(a-b)^{1}}{(a^2 + ab + b^2)} \cdot
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