Question

My watch was 3 minutes slow at 5 p.m. Tuesday and it was 5 minutes fast at 11 p.m. Wednesday. When did it give correct time? (a) Wednesday $4: 15$ a.m. (b) Wednesday $7: 30$ a.m (c) Tuesday $3: 45$ p.m. (d) None of these

Name: Problem 16, Chapter 20: The Pearson Guide to Objective Arithmetic for Competitive Examinations
Uploaded: 2022-02-10T04:55:35-08:00
Duration: 1 min 1 s
Channel: Manik Pulyani
Description: My watch was 3 minutes slow at 5 p.m. Tuesday and it was 5 minutes fast at 11 p.m. Wednesday. When did it give correct time? (a) Wednesday 4: 15 a.m. (b) Wednesday 7: 30 a.m (c) Tuesday 3: 45 p.m. (d) None of these

   My watch was 3 minutes slow at 5 p.m. Tuesday and it was 5 minutes fast at 11 p.m. Wednesday.
When did it give correct time?
(a) Wednesday $4: 15$ a.m.
(b) Wednesday $7: 30$ a.m
(c) Tuesday $3: 45$ p.m.
(d) None of these

The Pearson Guide to Objective Arithmetic for Competitive Examinations

Dinesh Khattar 2nd Edition

Chapter 20, Problem 16

Instant Answer

Solved by Expert Manik Pulyani

02/10/2022

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My watch was 3 minutes slow at 5 p.m. Tuesday and it was 5 minutes fast at 11 p.m. Wednesday. When did it give correct time? (a) Wednesday $4: 15$ a.m. (b) Wednesday $7: 30$ a.m (c) Tuesday $3: 45$ p.m. (d) None of these

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Key Concepts

Uniform Rate of Change

This concept refers to the idea that the error (fast or slow) of the watch changes at a constant rate over time. By assuming uniformity, one can linearly relate the amount of error at different times, which is essential for setting up the equations needed to find when the watch was accurate.

Linear Interpolation

In this context, linear interpolation involves using the two known error measurements at different times to create a linear equation. By solving this equation, one finds the exact moment when the clock error is zero, meaning the watch shows the correct time.

Clock Error Analysis

This involves evaluating the deviation of a clock's time from the correct time and understanding how this deviation changes over time. By analyzing the error at different points and assuming a uniform rate of change, one can determine the specific time at which the clock will display the correct time.

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