00:01
Solving problem 44 of chapter 15.
00:06
Using the akel rule for n plus 2 pi electrons show why this molecule behaves as an aromatic molecule.
00:15
So let's start drawing the structure of the molecule.
00:20
We have a benzene ring.
00:26
And on this side we have a five -member ring.
00:41
Oxygen.
00:43
Double bond oxygen.
00:44
The non -pairs, we have an hydrogen in here, and negative charge in here, and the plus on the nitrogen.
01:02
And the book is also telling us that this molecule, it does also a second resonance structure.
01:10
So hydrogen, double bond, oxygen, 2, 24, the second double bond is there where it was before and then we have the benzene ring.
01:45
Okay, so let's write down acker rule to verify when a compound is aromatic or not for n plus 2, where n can be any integer like 0, 1, 2, etc, etc, etc.
02:18
So when the molecule is written in this form, it's not very easy to see, to verify, the aromaticity of this portion especially.
02:28
This portion, we already know that the total of the electrons is six because it's a benzene ring...